0=6x^2-5x-50

Solution for 0=6x^2-5x-50 equation:

0=6x^2-5x-50

We move all terms to the left:

0-(6x^2-5x-50)=0

We add all the numbers together, and all the variables

-(6x^2-5x-50)=0

We get rid of parentheses

-6x^2+5x+50=0

a = -6; b = 5; c = +50;
Δ = b2-4ac
Δ = 52-4·(-6)·50
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-35}{2*-6}=\frac{-40}{-12}
=3+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+35}{2*-6}=\frac{30}{-12}
=-2+1/2
$